hi

Can u give the solution  please

vinay

for a given product, the sum of the variables is minimum when theyre equal

since product has a^2 , b^3 and c^1, break the exp. (a+b+c) such that upon multiplying the constituents, the powers of a, b and c are reflected.

That is, we have to find

a/2 +a/2 +b/3+ b/3 + b/3 +c (which is = a+b+c)

now the product of above variables= a^2*b^3*c/ (2^2 * 3^3)

since we already know the value of numerator = 256/27, substitute it in the given equation and simplify... u'l have 2^6/ 3^6

let each of a/2 b/3 and c =k

then 2^6/3^6=k (since there are six terms being multiplied in the expression, each of which =k)

k=2/3

what we have to find is 6k (sum minimum, when all terms equal, in this case =k)

so we have 6k= 2/3*6= 4

peace out!